h^2-16h-192=0

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Solution for h^2-16h-192=0 equation:



h^2-16h-192=0
a = 1; b = -16; c = -192;
Δ = b2-4ac
Δ = -162-4·1·(-192)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-32}{2*1}=\frac{-16}{2} =-8 $
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+32}{2*1}=\frac{48}{2} =24 $

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